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Empirical Formula Calculator
Write the masses of Carbon, oxygen, and hydrogen and then press the calculate to get the mole and mole ratio using empirical formula calculator
Table of Contents:
What is Empirical Formula?
The empirical formula for a compound provides the most straightforward ratio of the number of various atoms that are present. The sulfur and oxygen molecules, sulfur monoxide, and disulfuric dioxide have the same empirical formula. They have the same molecular formulas, which indicate how many atoms are present in each molecule of a chemical compound.
Examples of Empirical Formula
Example 1:
Calculate the mole and mole ratio if the mass of carbon = 121, Hydrogen = 141, and Oxygen = 181
Solution:
| Element | C | H | O |
| Mass | 121 g | 141 g | 181 g |
| Mole | 121/12 | 141/1.008 | 181/16.01 |
| Mole | 10.08 | 139.88 | 11.31 |
| Divide by small | 10.08/10.08 | 139.88/10.08 | 11.31/10.08 |
| Mole Ratio | 1 | 14 | 2 |
Example 2:
Calculate the mole and mole ratio if the mass of carbon = 32, Hydrogen = 24, and Oxygen = 54
| Element | C | H | O |
| Mass | 32 g | 24 g | 54 g |
| Mole | 32 /12 | 24 /1.008 | 54 /16.01 |
| Mole | 2.67 | 23.81 | 3.37 |
| Divide by small | 2.67 / 2.67 | 23.81 / 2.67 | 3.37 / 2.67 |
| Mole Ratio | 1 | 9 | 2 |
Here are some other results of the empirical formula calculator
| C | Mole | Mole ratio | H | Mole | Mole ratio | O | Mole | Mole ratio |
| 10 g | 0.83 | 1 | 14 g | 13.89 | 17 | 18 g | 1.12 | 2 |
| 2 g | 0.17 | 1 | 4 g | 3.97 | 24 | 8 g | 0.5 | 3 |
| 21 g | 1.75 | 1 | 41 g | 40.67 | 24 | 81 g | 5.06 | 3 |
| 31 g | 2.58 | 1 | 51 g | 50.6 | 20 | 71 g | 4.43 | 2 |
| 234 g | 19.5 | 1 | 512 g | 507.94 | 27 | 321 g | 20.5 | 2 |
| 34 g | 2.83 | 3 | 12 g | 11.9 | 10 | 21 g | 1.31 | 1 |
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